A sample of gas have a volume of 500c3 of 45c what volume with the gas occupy at 0c when the pressure is constant.
Anonymous has derived the end formula of
(V1/T1) = (V2/T2)
Just plug in those values he gave you.
U don't understand
V1/T1=V2/T2 500CM^3/45+273=V2/0+273 =429.25
yeah samuel is right
Initial temp = 273 + 45 = 318 deg K
Final temp = 273 deg K
P V = n R T
P, n R constant so
V / T = n R/P same before and after
V/ 273 = 45 cups or whatever you mean / 318
V = 45 *(273/318) whatevers
429.2cm3
To determine the volume of gas at 0°C when the pressure is constant, we can use Charles's Law, which states that the volume of a given amount of gas is directly proportional to its temperature in Kelvin (K), provided that the pressure and amount of gas remain constant.
First, we need to convert the given temperature from Celsius (°C) to Kelvin (K). The relationship between Celsius and Kelvin is given by the formula K = °C + 273.15.
So, let's convert the given temperature of 45°C to Kelvin:
T(K) = 45°C + 273.15 = 318.15 K
Next, we can set up a proportion to solve for the new volume:
V1 / T1 = V2 / T2
Where:
V1 = initial volume of the gas (500 cm³)
T1 = initial temperature of the gas in Kelvin (318.15 K)
V2 = final volume of the gas (unknown)
T2 = final temperature of the gas in Kelvin (0 K or -273.15°C)
Now, we can plug in the given information into the proportion and solve for V2:
(V1 / T1) = (V2 / T2)
(500 cm³ / 318.15 K) = (V2 / 273.15 K)
Cross-multiplying, we get:
(500 cm³) × (273.15 K) = V2 × (318.15 K)
Simplifying the equation:
V2 = (500 cm³ × 273.15 K) / 318.15 K
Calculating the result:
V2 ≈ 430.41 cm³
Therefore, the gas will occupy approximately 430.41 cm³ at 0°C when the pressure is held constant.