A water wheel at a mill has a
radius of 4.97 m, and generates
4530 N*m of torque.
If the water
pushes tangent to the edge,
how much force does it exert on
the wheel?
To find the force exerted by the water on the wheel, we can use the equation:
Torque = Force x Radius
Given that the radius of the water wheel is 4.97 m and the torque is 4530 N*m, we can rearrange the equation to solve for force:
Force = Torque / Radius
Substituting the given values into the equation:
Force = 4530 N*m / 4.97 m
Calculating the force:
Force = 911.47 N
Therefore, the water exerts a force of approximately 911.47 N on the wheel.
To find the force exerted by the water on the wheel, we need to use the relationship between torque and force.
The torque (T) generated by the water wheel is given as 4530 N*m. The torque can be calculated using the formula:
T = r * F
Where:
T is the torque
r is the radius of the wheel
F is the force exerted on the wheel
In this case, the radius (r) of the wheel is given as 4.97 m. We can rearrange the formula to solve for the force (F):
F = T / r
Plugging in the values, we have:
F = 4530 N*m / 4.97 m
Calculating this, we find:
F ≈ 911.86 N
Therefore, the water exerts a force of approximately 911.86 N on the wheel.