A skier leaves a ramp and flies 2 meters into the air before falling 5 meters and landing lower on the mountain. Compare the KE and PE as he leaves the ramp, at his highest point in the air, and when he lands on the ground.
A javelin thrower finds they can throw a 800g javelin 50m, a 600g javelin 58m and a 250 g spear the same size only 30m. Explain why the same amount of throwing energy produces these 3 results.
If the diver is moving at 1.4 m/s when she is 2.2 m above the pool what is her KE and PE? (round answer to 1 decimal place and use proper units.)
As a diver jumps from the board potential and kinetic energy are
transformed into one another. Describe the 2 types of energy as
the diver moves from the board to the water.
So we're both here, huh?
@anon yes T_T
To compare the kinetic energy (KE) and potential energy (PE) of the skier at different points, we need to understand the formulas for calculating these energies.
1. KE: The formula for kinetic energy is KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.
2. PE: The formula for potential energy is PE = m * g * h, where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height of the object.
Now let's compare the energies of the skier at different points:
1. As the skier leaves the ramp, assuming no significant loss of energy due to friction or air resistance, the only form of energy the skier has is potential energy. The potential energy is PE = m * g * h, where m is the skier's mass, g is the acceleration due to gravity, and h is the height. So, at this point, the skier has potential energy but no kinetic energy.
2. At the skier's highest point in the air, when he/she is momentarily motionless, the velocity becomes zero, and thus the kinetic energy is zero. However, the skier is still at a height above the ground, so there is still potential energy.
3. When the skier lands on the ground, the potential energy becomes zero because the skier is at ground level, and there is no height. However, the skier now has kinetic energy since he/she is in motion. The kinetic energy depends on the skier's mass and velocity.
Regarding the javelin thrower's results, we observe that the distance thrown depends not only on the throwing energy but also on the mass of the object being thrown.
1. The 800g javelin is thrown 50m: This means that the thrower has applied enough energy to overcome the air resistance and gravity to propel the javelin to that distance.
2. The 600g javelin is thrown 58m: Due to its lower mass compared to the 800g javelin, it requires less energy to throw it the same distance. The thrower has supplied enough energy to achieve a greater distance.
3. The 250g spear is thrown only 30m: With even less mass, the spear requires even less energy to achieve a certain distance. The thrower has supplied enough energy to propel the spear to its specific distance.
In all three cases, the same amount of throwing energy produces different results due to the difference in the mass of the objects. The lighter objects require less energy to attain the same distance because they are easier to accelerate.
For the diving question, we need to calculate the kinetic energy (KE) and potential energy (PE) of the diver:
Given:
- Velocity (v) = 1.4 m/s
- Height (h) = 2.2 m
- Mass of the diver (m) is not provided.
1. KE: The formula for kinetic energy is KE = 1/2 * m * v^2, where m is the mass of the diver and v is the velocity.
To calculate the KE, we need the mass of the diver. Once we have that information, we can use the given velocity to calculate the KE.
2. PE: The formula for potential energy is PE = m * g * h, where m is the mass of the diver, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height.
To calculate the PE, we need the mass of the diver. Once we have that information, we can use the given height to calculate the PE.
Unfortunately, without the mass of the diver, we cannot calculate the exact values of KE and PE. However, once the mass is known, plugging in the given values into the formulas will provide the answers in the appropriate units.