What mass of water will be needed to change the temperature 25 Celsius using 4532 J of heat energy
q = mass x specific heat x delta T
4532 = mass x specific heat x 25. You must look up the specific heat of water. I THINK, but you should confirm, it is 4.18 J/g*C.
Well, let's dive into this one! To find the mass of water needed to change the temperature, we can use the equation:
Q = mcΔT
Where:
Q is the heat energy (4532 J),
m is the mass of water we're trying to find,
c is the specific heat capacity of water (approximately 4.18 J/g°C),
ΔT is the change in temperature (25°C starting from what? We need the initial temperature too).
Now, if we put all these ingredients together, we can calculate the mass of water. But remember, this equation is trickier than a water balloon fight! So, make sure to provide the starting temperature so I can help you calculate the mass accurately.
To calculate the mass of water needed to change the temperature using heat energy, we can use the equation:
q = mcΔT
where:
q is the heat energy,
m is the mass of water,
c is the specific heat capacity of water,
ΔT is the change in temperature.
In this case, we know:
q = 4532 J (given)
ΔT = 25°C (given)
The specific heat capacity of water, c, is approximately 4.18 J/g°C.
Substituting the values into the equation, we have:
4532 J = m * 4.18 J/g°C * 25°C
To solve for m, we can rearrange the equation as follows:
m = 4532 J / (4.18 J/g°C * 25°C)
m ≈ 43.7 grams
Therefore, approximately 43.7 grams of water will be needed to change the temperature by 25°C using 4532 J of heat energy.
To find the mass of water needed to change its temperature using a given amount of heat energy, you need to use the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C.
The formula to calculate the heat energy is:
Q = m * c * ΔT
Where:
Q is the heat energy (in joules),
m is the mass of water (in grams),
c is the specific heat capacity of water (in J/g°C),
ΔT is the change in temperature (in °C).
Rearranging the formula, we can solve for m:
m = Q / (c * ΔT)
Now let's substitute the given values into the equation:
Q = 4532 J
c = 4.18 J/g°C
ΔT = 25°C
m = 4532 J / (4.18 J/g°C * 25°C)
m = 4532 J / (104.5 J/g)
m ≈ 43.35 g
Therefore, approximately 43.35 grams of water would be needed to change the temperature by 25°C using 4532 J of heat energy.