A resultant force of 25 Newton acts on mass
of 0.5 kg standing from rest.
find: a) the acceleration in m/s square
b) the final velocity after 20 seconds
c) the distance moved in meter
A resultant force of 25 Newton acts on mass
of 0.5 kg standing from rest.
find: a) the acceleration in m/s square
b) the final velocity after 20 seconds
c) the distance moved in meter
a = F/m = 25/ 0.5 = 50 m/s^2
v = Vinitial + a * t = 0 + 50 * 20 = 1,000 m/s
x = initial +Vinitial * t + ( 1/2) a *t^2 = 0 + 0 + 25* 400
= 25 * 400 = 10,000 meters
To find the answers to the given questions, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).
Given Data:
Force (F) = 25 Newton
Mass (m) = 0.5 kg
a) To find the acceleration (a):
We can rearrange the equation F = ma to solve for acceleration.
a = F/m
Substituting the values:
a = 25 N / 0.5 kg = 50 m/s²
Therefore, the acceleration is 50 m/s².
b) To find the final velocity (v) after 20 seconds:
We can use the kinematic equation: v = u + at, where
v = final velocity
u = initial velocity (which is 0 as the object starts from rest)
a = acceleration = 50 m/s²
t = time = 20 seconds
Substituting the values:
v = 0 + (50 m/s²)(20 s) = 1000 m/s
Therefore, the final velocity after 20 seconds is 1000 m/s.
c) To find the distance moved (s):
We can use another kinematic equation: s = ut + (1/2)at², where
s = distance moved
u = initial velocity (which is 0 as the object starts from rest)
a = acceleration = 50 m/s²
t = time = 20 seconds
Substituting the values:
s = 0 + (1/2)(50 m/s²)(20 s)² = 0 + 25 m/s² * 400 s² = 10,000 m
Therefore, the distance moved in 20 seconds is 10,000 m.
To solve this problem, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula we can use is:
a = F/m
where:
a = acceleration in m/s^2
F = resultant force in Newtons
m = mass in kg
a) The acceleration can be calculated by dividing the resultant force (25 N) by the mass (0.5 kg):
a = 25 N / 0.5 kg
a = 50 m/s^2
Therefore, the acceleration is 50 m/s^2.
b) To find the final velocity after a given time, we can use the equation of motion:
v = u + at
where:
v = final velocity
u = initial velocity (which is 0 as the object was at rest)
a = acceleration
t = time
Since the initial velocity (u) is 0, the equation simplifies to:
v = at
Using the values given, we can now find the final velocity after 20 seconds:
v = 50 m/s^2 * 20 s
v = 1000 m/s
Therefore, the final velocity after 20 seconds is 1000 m/s.
c) To find the distance moved, we can use another equation of motion:
s = ut + (1/2)at^2
where:
s = distance
u = initial velocity
t = time
a = acceleration
Again, as the initial velocity (u) is 0, the equation simplifies to:
s = (1/2)at^2
Using the values given, we can now calculate the distance moved:
s = (1/2) * 50 m/s^2 * (20 s)^2
s = 0.5 * 50 m/s^2 * 400 s^2
s = 0.5 * 50 * 400 m
s = 10,000 meters
Therefore, the distance moved is 10,000 meters.