There are 100 students in the LEVEL 3 accounting class. 75 of them passed Business Mathematics while 40 passed in Use of English. How many students passed in both subjects?

Well, it seems like these students are experts at crunching numbers but not so great at using proper English. Just like their accounting skills, let's calculate the answer in a fun way!

So, out of the 100 students in the accounting class, 75 passed Business Mathematics and 40 passed Use of English. Now, let's imagine these students as pieces of delicious pizza.

If we have 75 slices of pizza for Business Mathematics and 40 slices of pizza for Use of English, we want to find out how many slices we have that are the perfect combination of both.

So, let's set up our pizza equation:

Total number of slices (students) in both subjects = Slices for Business Mathematics + Slices for Use of English - Extra toppings (overlap)

Now, let's plug in the numbers:

Total number of slices in both subjects = 75 + 40 - Extra toppings (overlap)

Since we want to calculate the overlap or the number of students who passed in both subjects, let's call that "X".

Total number of slices in both subjects = 75 + 40 - X

Since we know the total number of students in the accounting class is 100, we can write:

Total number of slices in both subjects = 100 - X

And since we want to find out how many students passed in both subjects (the overlap), we'll set our equation equal to the number of students who passed in both subjects:

100 - X = X

Now, let's solve for X:

100 = 2X

X = 50

So, it looks like 50 students passed in both Business Mathematics and Use of English. And just like a perfectly baked pizza, they deserve a round of applause! 🍕👏

×=15

N (ue)=(b)+n (e)-n (bne)=100=75+40-x=115-x=100=-x=100-15=-x=-15x=15

To find out how many students passed in both subjects, we need to determine the number of students who passed in Business Mathematics and Use of English and then find the intersection between the two.

From the information given, we know that 75 students passed in Business Mathematics and 40 students passed in Use of English. However, we don't have any information about the correlation between these two subjects. Therefore, we cannot determine the exact number of students who passed in both subjects without additional information.

However, we can identify a potential range for the number of students who passed in both subjects. Since there are 100 students in the accounting class, the maximum number of students who can pass in both subjects is the smaller of the two counts, which is 40 (the number of students who passed Use of English). Similarly, the minimum number of students who can pass in both subjects is 0, as it's possible that none of the students who passed in Business Mathematics also passed in Use of English.

Hence, without further information, we can only conclude that the number of students who passed in both subjects is between 0 and 40.

75 + 40 = 115

115 - x = 100
x = 15
or draw Venn Diagram
75 -x ..... x ..... 40- c
75-x + x + 40 - x = 100
115 -x = 100
x = 15 again