Calculate the Mass of oxygen which would be envove on heating 5g of potassium trioxochlorate v
Yes
Please
impatient much?
2KClO3 ==> 2KCl + 3O2
so, how many moles of KClO3 in 5g?
The equation tells you it will produce 3/2 that many moles of O2
so how many grams is that?
To calculate the mass of oxygen released when heating 5g of potassium trioxochlorate(V) (KClO3), we need to consider the molar ratio between KClO3 and O2, as well as the molar mass of each compound.
First, let's determine the balanced chemical equation for the reaction of potassium trioxochlorate(V) decomposition:
2KClO3 --> 2KCl + 3O2
From the balanced equation, we can see that 2 moles of KClO3 produce 3 moles of O2.
Next, we need to calculate the molar mass of KClO3 and O2. The molar mass of KClO3 can be calculated using the atomic masses of potassium (K), chlorine (Cl), and oxygen (O):
Molar mass of KClO3 = (1 * atomic mass of K) + (1 * atomic mass of Cl) + (3 * atomic mass of O)
By referring to the periodic table, we can find:
Atomic mass of K = 39.10 g/mol
Atomic mass of Cl = 35.45 g/mol
Atomic mass of O = 16.00 g/mol
Plugging these values into the equation:
Molar mass of KClO3 = (1 * 39.10) + (1 * 35.45) + (3 * 16.00)
= 39.10 + 35.45 + 48.00
= 122.55 g/mol
Now we can calculate the number of moles of KClO3 using the given mass:
Number of moles = Mass / Molar mass
= 5g / 122.55 g/mol
≈ 0.0408 mol (rounded to four decimal places).
Since the molar ratio between KClO3 and O2 is 2:3, we can use this ratio to find the moles of O2 produced:
Number of moles of O2 = Number of moles of KClO3 * (3/2)
≈ 0.0408 mol * (3/2)
≈ 0.0611 mol (rounded to four decimal places).
Finally, to calculate the mass of oxygen, we can use the molar mass of O2:
Mass of O2 = Number of moles of O2 * Molar mass of O2
= 0.0611 mol * 32.00 g/mol (molar mass of O2)
≈ 1.9562 g (rounded to four decimal places).
Therefore, the mass of oxygen released when heating 5g of potassium trioxochlorate(V) is approximately 1.9562 grams.