How many moles of sodium hydroxide are produced if 2.0 moles of sodium metal are reacted with excess water?
Na + H2O ---> NaOH + H2
Balance the equation.
2Na + 2H2O ---> 2NaOH + H2
The equation tells you that 2 mols Na will produce 2 mol NaOH.
The balanced equation for the reaction is:
2Na + 2H2O ➡️ 2NaOH + H2
From the equation, we can see that 2 moles of sodium (Na) react with 2 moles of water (H2O) to produce 2 moles of sodium hydroxide (NaOH).
Given that 2.0 moles of sodium (Na) are reacted, we can conclude that 2.0 moles of sodium hydroxide (NaOH) will be produced.
To determine the number of moles of sodium hydroxide (NaOH) produced, we need to use the balanced chemical equation and the stoichiometry of the reaction.
The balanced chemical equation is: Na + H2O ---> NaOH + H2
From the equation, we can see that 1 mole of sodium (Na) reacts with 1 mole of water (H2O) to produce 1 mole of sodium hydroxide (NaOH) and 1 mole of hydrogen gas (H2). This indicates a stoichiometric ratio of 1:1:1:1.
Given that 2.0 moles of sodium (Na) are reacted, we can conclude that 2.0 moles of NaOH are produced.
So, 2.0 moles of sodium hydroxide (NaOH) are produced if 2.0 moles of sodium metal are reacted with excess water.