Construct ∆ ABC in which |AB|=5cm,|AC|=6cm and |BC|=9cm
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Question
To construct triangle ABC with the given side lengths, we can follow these steps:
Step 1: Draw a straight line segment AB of length 5 cm.
Step 2: At point A, draw a ray (an infinite line extending in one direction) with any angle.
Step 3: Using a compass, set the radius to 6 cm and place the compass point on point A. Draw an arc that intersects the ray you drew in step 2, and label this point of intersection as C.
Step 4: With the same compass radius, place the compass point on point C and draw an arc that intersects the line segment AB. Label this point of intersection as B.
Step 5: Draw a straight line segment BC to complete the triangle.
Now, triangle ABC is constructed, where |AB| = 5 cm, |AC| = 6 cm, and |BC| = 9 cm.
construct BC=9
with center at B, draw circle with radius 5
with center at C, draw circle with radius 6
the two circles intersect at A