Ugoma pulls a bucket from a well that is 50 meters deep with The rope inclined at 30 degree to the horizontal. if the force applied is 30 Newton what is the work done and what power does she possesses if it was done in 10 seconds
I need an answer to the first question i ask.
Please
Is there a pulley system involved? How do you pull a bucket up with a rope inclined 30 deg from horizontal?
Anyway the force times the distance pulled in the direction of the force = work done = 30 N + 50 m = 1500 Joules
power = 1500 Joules / 10 seconds = 150 watts
30 N + 50 m
Typo
30 N * 50 m
To find the work done by Ugoma in pulling the bucket and the power she possesses, we need to use the formulas for work and power.
1. Work (W) is given by the formula:
W = F * d * cos(θ)
where F is the force applied, d is the distance moved, and θ is the angle between the force and the displacement.
2. Power (P) is given by the formula:
P = W / t
where W is the work done and t is the time taken.
Let's break it down step-by-step:
Step 1: Calculate the vertical distance moved (d).
The given depth of the well is 50 meters. Since the rope is inclined at 30 degrees, the vertical distance moved will be less than the actual depth. We can calculate it using trigonometry.
Vertical distance (d) = Depth of well * sin(θ)
= 50 * sin(30°)
= 50 * 0.5
= 25 meters
Step 2: Calculate the work (W).
W = F * d * cos(θ)
= 30 * 25 * cos(30°)
To calculate the value of cos(30°), we'll need to use a calculator or a table.
Cosine of 30 degrees is approximately 0.866.
W = 30 * 25 * 0.866
≈ 649.5 Joules
Therefore, the work done by Ugoma is approximately 649.5 Joules.
Step 3: Calculate the power possessed (P).
P = W / t
= 649.5 / 10
P ≈ 64.95 Watts
Therefore, Ugoma possesses approximately 64.95 Watts of power.
So, the work done by Ugoma is approximately 649.5 Joules, and she possesses approximately 64.95 Watts of power.