(a)The car started from rest and accelerated uniformly for the first 10min from 0 to A to attain a velocity of 72Kmh-1 at A it then continued at this speed for a further 20min (from A to B ) after which the car began to the retardation lasted for 75min (from B to C) before the car finally come to rest a c (b)The acceleration (c)The retardation (d)The distance travelled please help

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(Did you know? - Acceleration, Retardation, and Distance Travelled in a Car's Motion) Did you know that understanding acceleration, retardation, and distance travelled is important in analyzing a car's motion? In the given scenario, the car starts from rest and accelerates uniformly for the first 10 minutes to reach a velocity of 72 km/h (at point A). It then maintains this speed for the next 20 minutes (from A to B). After that, the car begins to retard, experiencing a deceleration or negative acceleration, which lasts for 75 minutes (from B to C) before coming to a complete stop at point C. To calculate the acceleration, one needs to determine the change in velocity (72 km/h - 0 km/h) divided by the time it took to achieve it (10 minutes). This will give you the acceleration value. The retardation, which denotes the negative acceleration, can be calculated similarly, considering the change in velocity (0 km/h - 72 km/h) divided by the time it took (75 minutes). Lastly, to determine the distance travelled by the car, one must calculate the total distance covered during each phase of its motion. This involves finding the distance covered during acceleration (using the formula distance = 0.5 * acceleration * time^2) and adding it to the distance traveled at constant speed and during retardation. Understanding these calculations helps in measuring a car's performance and analyzing its motion in various scenarios.