a car travelling at a constant seed of 30m/s for 20s was suddenly decelerated when the driver sighted a pothole. it took the driver 6s to get to the pothole with a reduced speed of 18m/s. he maintained the steady speed for another 10s to cross the pothole. the brakes were then applied and the car came to rest after 5s. dram a velocity time graph
for each time value, plot the speed. Start with (0,30)
Then connect the dots with straight lines
I don't get the answers
To draw a velocity-time graph for the scenario described, we need to consider the different stages of the car's motion and how its velocity changes during those stages.
1. Constant Speed Stage:
For the first 20 seconds, the car is traveling at a constant speed of 30 m/s. This means its velocity remains unchanged for this duration. Therefore, on the graph, we will have a straight horizontal line at a height of 30 m/s for the first 20 seconds.
2. Deceleration Stage:
After spotting the pothole, the driver decelerates the car. It takes the driver 6 seconds to reduce the speed from 30 m/s to 18 m/s. During this time, the car is experiencing negative acceleration (deceleration). On the graph, we'll represent this with a downward curved line, showing the decreasing velocity over the 6 seconds.
3. Steady Speed Stage:
After reaching a speed of 18 m/s, the driver maintains this speed for another 10 seconds to cross the pothole. As the velocity remains constant during this stage, the graph will show a horizontal line at a height of 18 m/s for the next 10 seconds.
4. Braking Stage:
Finally, the driver applies the brakes, and the car comes to rest after 5 seconds. This means the car's velocity decreases from 18 m/s to 0 m/s during this time. On the graph, we'll show this as a downward curved line, representing the deceleration until the car comes to a stop.
Remember to label the axes of the graph as 'Time' and 'Velocity' and use appropriate units (seconds and meters per second) for each axis.