Chlorine gas diffuse through a porous at the rate of 2.1cm cube.calculate the rate of carbon (iv) oxide under the same condition
mm stands for molar mass.
(rate Cl2/rate CO2) = sqrt (mm CO2/mm Cl2)
Substitute and solve. Post your work if you get stuck.
To calculate the rate of carbon (IV) oxide diffusion under the same conditions, we need to know the diffusion coefficient of carbon (IV) oxide and the thickness of the porous material.
The diffusion rate of a gas through a porous material can be calculated using Fick's Law:
Rate of diffusion = (Diffusion coefficient * Area * Change in concentration) / Thickness
However, since we don't have the diffusion coefficient or the thickness of the porous material for carbon (IV) oxide, we cannot directly calculate its diffusion rate.
Please provide the necessary information so that we can assist you further.
To calculate the rate of carbon (IV) oxide (CO2) under the same conditions as the given chlorine gas, you need to apply Graham's Law of Diffusion.
Graham's Law states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
1. Determine the molar masses of chlorine gas (Cl2) and carbon (IV) oxide (CO2). The molar mass of Cl2 is approximately 70.9 g/mol, and the molar mass of CO2 is approximately 44.0 g/mol.
2. Using the given diffusing rate for chlorine gas (2.1 cm^3), assume that the time taken for it to diffuse is the same for carbon (IV) oxide. We will use this assumption to compare the two rates.
3. In Graham's Law, the ratio of the rates of diffusion is equal to the square root of the ratio of the molar masses of the gases. Therefore, the equation for this comparison is:
(rate of CO2) / (rate of Cl2) = sqrt(molar mass of Cl2 / molar mass of CO2)
(rate of CO2) / 2.1 cm^3 = sqrt(70.9 g/mol / 44.0 g/mol)
4. Rearrange the equation to solve for the rate of CO2:
(rate of CO2) = 2.1 cm^3 * sqrt(44.0 g/mol / 70.9 g/mol)
(rate of CO2) = 2.1 cm^3 * sqrt(0.62)
(rate of CO2) = 2.1 cm^3 * 0.788
(rate of CO2) ≈ 1.6508 cm^3
Therefore, the rate of carbon (IV) oxide under the same conditions is approximately 1.6508 cm^3.