An elevator containing passenger has total mass of 1700kg. The elevator accelerates updoward . What tension in needed in the cable to accelerate the elevator from rest to a velocity of 4.5m.s upward in 8,8s
To find the tension in the cable, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration (F = ma). In this case, the net force is the tension in the cable.
Given:
Mass of the elevator (m) = 1700 kg
Acceleration of the elevator (a) = ?
Final velocity (v) = 4.5 m/s
Time taken (t) = 8.8 s
To find the acceleration, we can use the formula:
a = (v - u) / t
Where:
u is the initial velocity, which is 0 since the elevator is starting from rest.
Plugging in the given values:
a = (4.5 - 0) / 8.8
= 0.511 m/s²
Now that we have the acceleration, we can find the tension in the cable using Newton's second law:
F = ma
= 1700 kg * 0.511 m/s²
= 869.37 N
Therefore, the tension in the cable needed to accelerate the elevator from rest to a velocity of 4.5 m/s upward in 8.8 s is approximately 869.37 N.