How many mol of nitrogen monoxide gas (N2) are in a 1.49 L container at standard temperature and pressure?
8.97 x 1023 mol N2
2.14 x 10^–24 mol N2
6.65 x 10^–2 mol N2
2.89 x 10^1 mol N2
Nitrogen monoxide doesn't do it. Is that N2O or NO.
@DrBob222 what are you talking about which one is it?
To determine the number of moles of nitrogen monoxide gas (N2) in a 1.49 L container at standard temperature and pressure (STP), we can use the ideal gas law. The ideal gas law equation is expressed as:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in L)
n = number of moles
R = gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)
At STP, the temperature is 273.15 K and the pressure is 1 atm.
Let's calculate the number of moles, n:
n = PV / RT
Plugging in the given values:
P = 1 atm
V = 1.49 L
R = 0.0821 L·atm/mol·K
T = 273.15 K
n = (1 atm * 1.49 L) / (0.0821 L·atm/mol·K * 273.15 K)
Now, calculate the value of n using a calculator:
n ≈ 0.0687 mol
Therefore, the correct answer is approximately 0.0687 mol. None of the given options match this value.