Find the force required to give a helicopter of mass 2000 kg an acceleration of 0.10g upward in Newtons.
Find the work done by this force to lift the helicopter 150 m into the air.
A helicopter's engine produces a maximum power of 100000 W. How many seconds would it take the helicopter to reach an altitude of 150m?
F = ma (include g)
work = force * distance
power = work/time
A toy helicopter flies forward with a force of 15 N into an oncoming wind of 10 N. The force of gravity pulls the helicopter down with a force of 5 N, but the propeller is providing an upward force of 10 N.
A toy helicopter flies forward with a force of 15 N into an oncoming wind of 10 N. The force of gravity pulls the helicopter down with a force of 5 N, but the propeller is providing an upward force of 10 N
To find the force required to give a helicopter of mass 2000 kg an acceleration of 0.10g upward, we can use Newton's second law of motion:
Force = mass * acceleration
First, let's convert the acceleration from g (acceleration due to gravity) to meters per second squared (m/s^2). The value of g is approximately 9.8 m/s^2.
Acceleration = 0.10g = 0.10 * 9.8 m/s^2 = 0.98 m/s^2
Now we can calculate the force:
Force = mass * acceleration = 2000 kg * 0.98 m/s^2 = 1960 N
Therefore, the force required to give the helicopter an acceleration of 0.10g upward is 1960 Newtons.
Next, to find the work done by this force to lift the helicopter 150 m into the air, we can use the formula:
Work = force * distance
Distance = 150 m
Force = 1960 N
Work = 1960 N * 150 m = 294,000 J (Joules)
Therefore, the work done by the force to lift the helicopter is 294,000 Joules.
Now, let's calculate how many seconds it would take the helicopter to reach an altitude of 150 m using the maximum power of its engine.
Power is defined as the rate at which work is done:
Power = Work / time
Given that the helicopter's engine produces a maximum power of 100,000 W, and the work done is 294,000 J, let's calculate the time:
Time = Work / Power = 294,000 J / 100,000 W = 2.94 seconds
Therefore, it would take approximately 2.94 seconds for the helicopter to reach an altitude of 150 m using the maximum power of its engine.