1) What is the wavelength associated with a 0.150 kg baseball with a velocity of 50.0 m/s?
This is the De Broglie wavelength.
wavelength = lambda = h/mv. h is Planck's constant which is 6.626E-34. m is given in the problem as is v.
Post your work if you get stuck.
To find the wavelength associated with a ball in motion, we can use the de Broglie wavelength equation:
wavelength = h / momentum
Where:
- wavelength is the de Broglie wavelength
- h is the Planck's constant (approximated as 6.626 x 10^-34 J.s)
- momentum is the product of the mass and velocity of the object
Given:
- mass = 0.150 kg
- velocity = 50.0 m/s
Let's plug these values into the equation:
wavelength = (6.626 x 10^-34 J.s) / (0.150 kg * 50.0 m/s)
First, let's calculate the momentum:
momentum = 0.150 kg * 50.0 m/s
momentum = 7.50 kg.m/s
Now, let's calculate the wavelength:
wavelength = (6.626 x 10^-34 J.s) / (7.50 kg.m/s)
wavelength ≈ 8.8353333333333333 x 10^-35 m
Therefore, the wavelength associated with a 0.150 kg baseball moving at 50.0 m/s is approximately 8.835 x 10^-35 meters.
To determine the wavelength associated with a moving object, we need to use the concept of de Broglie wavelength. The de Broglie wavelength is defined as:
λ = h / p
Where:
λ is the wavelength,
h is the Planck's constant (6.626 x 10^-34 J·s),
p is the momentum of the object.
To find the momentum of the baseball, we can use the equation:
p = m * v
Where:
m is the mass of the object,
v is the velocity of the object.
Given that the baseball has a mass of 0.150 kg and a velocity of 50.0 m/s, we can calculate the momentum:
p = (0.150 kg) * (50.0 m/s)
p = 7.50 kg·m/s
Now we can substitute the momentum into the de Broglie wavelength equation:
λ = (6.626 x 10^-34 J·s) / (7.50 kg·m/s)
Evaluating this expression, we find:
λ ≈ 8.835 x 10^-35 meters
Therefore, the wavelength associated with a 0.150 kg baseball moving at a velocity of 50.0 m/s is approximately 8.835 x 10^-35 meters.