Raj has built a cubical water tank with lid for his house with each outer edge 3 m long. He gets the outer surface of the tank excluding the base, covered with square tiles, of side 50 cm. Find how much he would spend for the tiles, if the cost of the tiles is rs.180 per dozen.
so each face is 6x6 tiles
There are six faces, so ...
Didn't get you
oh, come on.
3m = 6 * 50cm
6 faces, each with 36 tiles makes 216 tiles
216 * 180/12 = ____ total cost
To find out how much Raj would spend for the tiles, we need to determine the surface area of the sides of the cubical water tank, excluding the base.
The surface area of a cube is given by the formula: A = 6s^2, where A is the surface area and s is the length of each side.
In this case, the length of each side of the tank is given as 3 m. First, we need to convert this to centimeters, since the side length of the tiles is given in centimeters.
1 meter = 100 centimeters, so 3 meters = 3 x 100 = 300 centimeters.
Now, let's calculate the surface area of the tank:
A = 6s^2 = 6(300)^2 = 6(90000) = 540000 square centimeters.
Now, we need to find out how many square tiles will be required to cover this area.
The area of each tile is given as 50 cm x 50 cm = 2500 square centimeters.
To find the number of tiles, we divide the tank's surface area by the area of each tile:
Number of tiles = Surface area of tank / Area of each tile = 540,000 / 2500 = 216 tiles.
Since the cost of the tiles is given as Rs. 180 per dozen, we need to calculate the cost of 216 tiles in dozens.
Number of dozens = Number of tiles / 12 = 216 / 12 = 18 dozen.
Finally, we calculate the cost of the tiles:
Cost = Number of dozens x Cost per dozen = 18 x Rs. 180 = Rs. 3240.
Therefore, Raj would spend Rs. 3240 for the tiles.