find the 9th term of the Arithmetic progression 18, 12, 6, 0, -6...
I need help please
1st term ... 18
common difference ... 12 - 18 = -6
9th term ... 1st term plus 8 differences
To find the 9th term of an arithmetic progression, you need to know the first term (a1) and the common difference (d).
In the given arithmetic progression, the first term (a1) is 18, and the common difference (d) is -6, as each term is decreasing by 6.
To find the 9th term (an), you can use the following formula:
an = a1 + (n-1)d
Plugging in the values:
a9 = 18 + (9-1)(-6)
= 18 + 8(-6)
= 18 - 48
= -30
Therefore, the 9th term of the arithmetic progression is -30.
To find the 9th term of an arithmetic progression, you need to know the first term (a) and the common difference (d) between consecutive terms.
In the given arithmetic progression: 18, 12, 6, 0, -6...
The first term (a) is 18, and the common difference (d) is -6 - 0 = -6.
Now, we can use the formula to find the nth term of an arithmetic progression:
nth term (Tn) = a + (n - 1)d
Substituting the values we know:
T9 = 18 + (9 - 1)(-6)
Simplifying:
T9 = 18 + 8(-6)
T9 = 18 - 48
T9 = -30
Therefore, the 9th term of the given arithmetic progression is -30.