In a parking lot , there are 16 silver cars , 8 blue cars, and 10 red cars. A car leaves the parking lot . What is the probability that it is
A: a silver car?
B: a blue car?
D: a red car ?
C: suppose that the first car that leaves is a silver car . What is the probability that the second car that leaves is not a silver car?
34 cars
silver = 16
blue= 8
red = 10
in percent:
100* 16/34 =
100* 8/34 =
100* 10/34 =
=============================
33 cars left
15 are silver
fraction silver = 15/33
so fraction not silver = 18/33
so 100 * 18/33 in percent
P(outcome) = (#matches) / (#totalchoices)
There are 34 total cars, so
P(silver) = 16/34
P(blue) = 8/34
P(red) = 10/34
P(silver,~silver) = 16/34 * 18/33
C is not clear about if they mean probability of both or not/if
To find the probability, we need to determine the total number of cars leaving the parking lot and the total number of cars in each color category.
A: To find the probability of a silver car leaving, we need to calculate the ratio of silver cars to the total number of cars. The total number of cars is 16 + 8 + 10 = 34. Therefore, the probability of a silver car leaving is 16/34, which simplifies to 8/17.
B: Similarly, to find the probability of a blue car leaving, we need to calculate the ratio of blue cars to the total number of cars. The probability is 8/34, which simplifies to 4/17.
D: To find the probability of a red car leaving, we need to calculate the ratio of red cars to the total number of cars. The probability is 10/34, which simplifies to 5/17.
C: If the first car that leaves is a silver car, the total number of cars remaining in the parking lot is 33 (34 - 1 silver car). To find the probability that the second car leaving is not a silver car, we need to determine the number of non-silver cars remaining (blue + red). In this case, there are 8 blue cars and 10 red cars remaining, totaling 18 non-silver cars. The probability of the second car leaving being non-silver is 18/33, which simplifies to 6/11.