From XNH3(g)+YO2>ZNO(g)+QH2O(g).
A.4
B.7
C.6
D.5
I don't see a question here but I assume the equation is to be balanced.
4NH3(g) + 5O2 ==> 4NO(g) + 6H2O(g).
Merry Christmas ❄⛄
Sorry, but I'm unable to understand what you're asking. Could you please provide more context or clarify your question?
Bud your 2 years late to the party
fr
ok
To determine the coefficient values for X, Y, Z, and Q in the given balanced chemical equation, you need to use the law of conservation of mass. The law states that matter cannot be created or destroyed in a chemical reaction. This means that the number of atoms of each element on the reactant side must be equal to the number of atoms of each element on the product side.
Looking at the equation: XNH3(g) + YO2 → ZNO(g) + QH2O(g)
Let's start by balancing the nitrogen (N) atoms. There is 1 nitrogen atom on the left side (from NH3) and 1 nitrogen atom on the right side (from NO). Therefore, the coefficient for NH3 would be 1.
XNH3(g) + YO2 → ZNO(g) + QH2O(g)
Next, let's balance the hydrogen (H) atoms. There are 3 hydrogen atoms on the left side (from NH3) and 2 hydrogen atoms on the right side (from H2O). To balance this, we can multiply the water molecule on the right side by 3.
XNH3(g) + YO2 → ZNO(g) + 3QH2O(g)
Now let's balance the oxygen (O) atoms. There are 3 oxygen atoms on the right side (from 3H2O) and 2 oxygen atoms on the left side (from O2). To balance this, we need to multiply the O2 molecule on the left side by 3.
XNH3(g) + 3YO2 → ZNO(g) + 3QH2O(g)
Finally, let's balance the nitrogen (N) atoms again. There is 1 nitrogen atom on the left side (from NH3) and 1 nitrogen atom on the right side (from NO). This means that the coefficient for NH3 is 1, and the coefficient for NO should also be 1.
XNH3(g) + 3YO2 → ZNO(g) + 3QH2O(g)
So, the balanced equation is: XNH3(g) + 3YO2 → ZNO(g) + 3QH2O(g)
Therefore, the answer is:
A. The coefficient value for X is 1.
B. The coefficient value for Y is 3.
C. The coefficient value for Z is 1.
D. The coefficient value for Q is 3.