# statistics

a survey is to be conducted to determine the proportion of U.S. voters who support additional aid to African nations to fight poverty and HIV/AIDS. Of the proposed sammple sizes which is the smallest that will guarantee a margin of error of no more than 4% for a 90% confidence level?
a)225
b)325
c)425
d)525
e)625

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2. 👎 0
3. 👁 276
1. Formula:

n = [(z-value) * p * q]/E^2
...where n is the sample size you seek, z-value is obtained using a z-table for the confidence interval (90%) in the problem, p and q represent proportions, E is the maximum error, and ^2 means squared.

Substituting values:
n = [(1.645) * .5 * .5]/.04^2
...where 1.645 represents the 90% confidence interval, .5 represents p if no value is stated, q = 1 - p = 1 -.5 = .5, .04 is 4% in decimal form and represents the maximum error of estimate for a proportion.

Calculate and choose the closest answer. There may be differences in the answer due to methods used.

I hope this will help.

1. 👍 0
2. 👎 0
posted by MathGuru
2. 525

1. 👍 0
2. 👎 0
posted by itty

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