find the distance travelled when the final angular velocity is 20rad/s the angular acceleration is 2rad/s^2 and the time of motion is 5s.
75m
Please help me
find the distance travelled when the final angular velocity is 20rad/s the angular acceleration is 2rad/s^2 and the time of motion is 5s.
To find the distance traveled when the final angular velocity, angular acceleration, and time of motion are given, you need to use the following formula:
θ = ω_i * t + (1/2) * α * t^2
Where:
θ is the angle traveled
ω_i is the initial angular velocity
t is the time of motion
α is the angular acceleration
In this case, we need to find the distance traveled, which is equivalent to the angle traveled. The initial angular velocity (ω_i) is not given in the problem. Since this value is not provided, we will assume ω_i = 0 because it's not specified otherwise.
Now, substitute the given values into the formula:
ω_i = 0 (initial angular velocity)
ω_f = 20 rad/s (final angular velocity)
α = 2 rad/s^2 (angular acceleration)
t = 5 s (time of motion)
θ = 0 * 5 + (1/2) * 2 * 5^2
θ = 0 + (1/2) * 2 * 25
θ = (1/2) * 50
θ = 25 radians
Therefore, the distance traveled when the final angular velocity is 20 rad/s, the angular acceleration is 2 rad/s^2, and the time of motion is 5 s, is 25 radians.