What is the eighth term of the arithmetic sequence defined by the rule
A(n) = −12 + 2(n−1)?
-26******
4
2
-28
I am very sick! I probably shouldn't be taking a test, but oh well. so so so sorry!
To find the eighth term of an arithmetic sequence defined by the rule A(n) = -12 + 2(n - 1), you need to substitute 8 for n in the equation and solve for A(8).
The formula for an arithmetic sequence is A(n) = a + (n - 1)d, where a represents the first term of the sequence and d represents the common difference between consecutive terms.
In this case, a = -12 and d = 2. Plugging in these values into the equation A(n) = -12 + 2(n - 1), we get A(8) = -12 + 2(8 - 1).
First, simplify the term inside the parentheses: A(8) = -12 + 2(7).
Next, apply the multiplication: A(8) = -12 + 14.
Adding -12 and 14, we find that A(8) = 2.
Therefore, the eighth term of the sequence is 2.
Tn = a + d * (n-1)
T8 = -12 + 2*7
= -12 +14
= 2