Determine the force of gravitational attraction between the earth (mass = 5.98 x 1024 kg) and a 68.0-kg physics student if the student is standing at sea level, a distance of 5.38 x 106 meters from earth's center. HELP PLEASE
f = M * m * G / r^2 = 5.98E24 * 68.0 * 6.67E-11 / (5.38E6)^2 ... Newtons
To determine the force of gravitational attraction between the Earth and the physics student, you can use the formula for gravitational force:
F = (G * m1 * m2) / r^2
where:
F is the force of gravitational attraction,
G is the gravitational constant (approximately 6.67430 x 10^-11 N(m/kg)^2),
m1 is the mass of the Earth,
m2 is the mass of the physics student, and
r is the distance between the Earth's center and the student.
Now, let's substitute the given values into the formula.
m1 = 5.98 x 10^24 kg (mass of the Earth)
m2 = 68.0 kg (mass of the student)
r = 5.38 x 10^6 meters (distance from Earth's center to the student)
Plugging in these values:
F = (6.67430 x 10^-11 N(m/kg)^2 * 5.98 x 10^24 kg * 68.0 kg) / (5.38 x 10^6 meters)^2
Now, calculate the result step-by-step:
F = (6.67430 x 10^-11 N(m/kg)^2 * (5.98 x 10^24 kg) * 68.0 kg) / (5.38 x 10^6 meters)^2
F = (4.0020314 x 10^14 N(m^2/kg^2) * (4.070 x 10^26 kg)) / (2.89444 x 10^13 meters^2)
F ≈ 5.950 x 10^12 N
Therefore, the force of gravitational attraction between the Earth and the physics student is approximately 5.950 x 10^12 Newtons (N).
To determine the force of gravitational attraction between the Earth and a physics student, you need to use the formula for the gravitational force:
F = (G * m1 * m2) / r^2
Where:
- F is the force of gravitational attraction
- G is the gravitational constant (approximately 6.67430 x 10^-11 m^3 kg^-1 s^-2)
- m1 and m2 are the masses of the two objects (in this case, the Earth and the student)
- r is the distance between the centers of the two objects
Given that the mass of the Earth (m1) is 5.98 x 10^24 kg, the mass of the student (m2) is 68.0 kg, and the distance (r) is 5.38 x 10^6 meters, we can now calculate the force of gravitational attraction (F).
Plugging the values into the formula:
F = (6.67430 x 10^-11 * (5.98 x 10^24) * 68.0) / (5.38 x 10^6)^2
Calculating this equation will give us the answer:
F ≈ 6.67 x 10^23 Newtons
Therefore, the force of gravitational attraction between the Earth and the physics student is approximately 6.67 x 10^23 Newtons.