1.) Find the sum: (3x2 + 5x + 8) + (6x2 + 3x + 2)

2.) Find the difference: (8x2 + 6x + 3) - (4x2 + 3x + 2)

what fruit loop meant to say is that

(3x^2 + 5x + 8) + (6x^2 + 3x + 2)
= 3x^2+6x^2 + 5x+3x + 8+2
= 9x^2 + 8x + 10

(8x^2 + 6x + 3) - (4x^2 + 3x + 2)
= 8x^2-4x^2 + 6x-3x + 3-2
= 4x^2 + 3x + 1

alright one sec

@Fruit Delicious YT...

Your answer cannot be read as it is all left-aligned.

P.S.
This is pre-algebra, not high school

This isn't pre algebra this is algebra 1

To find the sum and difference of polynomials, we combine like terms. Here's how you can find the answers to the given questions:

1.) Find the sum: (3x^2 + 5x + 8) + (6x^2 + 3x + 2)

To find the sum of the given polynomials, we add the coefficients of like terms. In this case, since both polynomials have terms with the same degree (in this case, 2, 1, and 0), we can simply add the coefficients for each degree.

Adding the coefficients for each degree:

(3x^2 + 6x^2) + (5x + 3x) + (8 + 2)

9x^2 + 8x + 10

Therefore, the sum of the given polynomials is 9x^2 + 8x + 10.

2.) Find the difference: (8x^2 + 6x + 3) - (4x^2 + 3x + 2)

To find the difference of the given polynomials, we subtract the coefficients of like terms. In this case, since both polynomials have terms with the same degree (in this case, 2, 1, and 0), we can simply subtract the coefficients for each degree.

Subtracting the coefficients for each degree:

(8x^2 - 4x^2) + (6x - 3x) + (3 - 2)

4x^2 + 3x + 1

Therefore, the difference of the given polynomials is 4x^2 + 3x + 1.

1. b

2. 8
x
2
+
6
x
+
3

4
x
2

3
x

2

Next, group like terms:

8
x
2

4
x
2
+
6
x

3
x
+
3

2

Now, combine like terms:

(
8

4
)
x
2
+
(
6

3
)
x
+
(
3

2
)

4
x
2
+
3
x
+
1