how to find the percent of chloride in A 3.000 g sample of a soluble chloride is titrated with 52.60 mL of 0.200M AgNO3.
What is the percentage of the chloride in the sample?
Cl^- + AgNO3 ==> AgCl(s) + [NO3]^-
mols AgNO3 = M x L = ?
mols Cl^- from the equation showing 1 mol Cl^- to 1 mol AgNO3 = mols AgNO3.
grams Cl^- = mols Cl^- x atomic mass Cl (not Cl2) = ?
Then % Cl^- = (grams Cl/mass sample)*100 = ?
Post your work i you get stuck.
To find the percentage of chloride in the sample, we need to determine the number of moles of chloride and calculate it as a percentage of the sample weight.
Step 1: Calculate the number of moles of AgNO3 used in the titration.
Molarity (M) = moles of solute / liters of solution
0.200 M AgNO3 = x moles / 0.05260 L
x = 0.200 M * 0.05260 L
x = 0.01052 moles of AgNO3
Step 2: Determine the stoichiometry between AgNO3 and chloride ions.
From the balanced equation:
AgNO3 + Cl- → AgCl + NO3-
We can see that 1 mole of AgNO3 reacts with 1 mole of Cl- to form 1 mole of AgCl.
Step 3: Calculate the number of moles of chloride in the sample.
Since the moles of AgNO3 and chloride ions are equal, there are 0.01052 moles of chloride in the sample.
Step 4: Calculate the percentage of chloride in the sample.
Percentage of chloride = (moles of chloride / sample weight) * 100%
Sample weight = 3.000 g
Percentage of chloride = (0.01052 moles / 3.000 g) * 100%
Percentage of chloride = 0.3507 g of chloride / 3.000 g sample * 100%
Percentage of chloride = 11.69%
Therefore, the percentage of chloride in the sample is approximately 11.69%.
To find the percentage of chloride in the sample, we first need to calculate the number of moles of AgNO3 used in the titration. Then, we can use stoichiometry to determine the number of moles of chloride present in the sample. Finally, we can calculate the percentage of chloride in the sample by dividing the mass of chloride by the mass of the sample and multiplying by 100.
Here's how to solve it step by step:
1. Calculate the number of moles of AgNO3 used in the titration:
The volume of AgNO3 used is given as 52.60 mL, and the concentration of AgNO3 is 0.200 M.
Moles of AgNO3 = concentration (M) × volume (L)
Convert the volume from mL to L by dividing by 1000:
Moles of AgNO3 = 0.200 M × (52.60 mL / 1000 mL/L) = 0.01052 moles
2. Determine the stoichiometry between AgNO3 and chloride:
The balanced chemical equation for the reaction between AgNO3 and chloride is:
AgNO3 + Cl- → AgCl + NO3-
From the equation, we can see that 1 mole of AgNO3 reacts with 1 mole of chloride (Cl-). Therefore, the number of moles of chloride is also 0.01052 moles.
3. Calculate the mass of chloride:
The molar mass of chloride (Cl-) is 35.45 g/mol.
Mass of chloride = moles of chloride × molar mass of chloride
Mass of chloride = 0.01052 moles × 35.45 g/mol = 0.372 g
4. Calculate the percentage of chloride in the sample:
The mass of the sample is given as 3.000 g.
Percentage of chloride = (mass of chloride / mass of sample) × 100
Percentage of chloride = (0.372 g / 3.000 g) × 100 = 12.4%
Therefore, the percentage of chloride in the sample is 12.4%.