Find the area underneath the curve of y= sin(x/2) from 0 to 3π/4 show your graph as well.
∫[0,3π/4] sin(x/2) = -2cos(x/2) [0,3π/4]
= -2(cos(3π/8) - cos(0))
= 2(1 - cos(π/8))
= 2(1 - √(2+√2)/2)
= 2 - √(2+√2)
= -2(cos(3π/8) - cos(0))
= 2(1 - cos(π/8))
= 2(1 - √(2+√2)/2)
= 2 - √(2+√2)