A man is 5 times as old as his son. Five years ago, the sum of their ages
was 50. How old are they?
If the son's age is x, then
5x-5 + x-5 = 50
Let's assign variables to represent the unknown ages:
Let's say the son's age is x years.
The man's age is then 5x years.
Five years ago, the son's age was x - 5 years.
And the man's age was 5x - 5 years.
According to the given information, the sum of their ages five years ago was 50:
(x - 5) + (5x - 5) = 50
Simplifying the equation:
6x - 10 = 50
Adding 10 to both sides of the equation:
6x = 60
Dividing both sides of the equation by 6:
x = 10
Therefore, the son is 10 years old and the man is 5 * 10 = 50 years old.
To solve this problem, let's assign variables:
Let's call the son's current age "x" and the man's current age "5x".
According to the problem, five years ago, the sum of their ages was 50. So, we need to subtract 5 from each of their current ages.
The son's age five years ago would be (x - 5), and the man's age five years ago would be (5x - 5).
We are given that the sum of their ages was 50 five years ago, so we can write the equation:
(x - 5) + (5x - 5) = 50
Now, we can solve the equation to find the values of x (son's current age) and 5x (man's current age).
Combining like terms:
6x - 10 = 50
Adding 10 to both sides:
6x = 60
Dividing both sides by 6:
x = 10
So, the son's current age (x) is 10 years old.
Now we can find the man's current age:
5x = 5 * 10 = 50
Therefore, the man's current age is 50 years old, and the son's current age is 10 years old.