A bird moves across the sky at 50 m/s at an angle of 15 degrees above the ground. The bird is carrying a piece of food, it drops the food 200 meters above the ground. When does the food hit the ground, and what is the horizontal distance of the food since it was dropped?
vertical speed = 50 sin15° = 12.94 m/s
horizontal speed = 50 cos15° = 48.30 m/s
Upon release, the height of the food t seconds after release is
h = 200 + 12.94t - 4.9t^2
so find t when h=0
use that to find the horizontal distance