The total amount under a paid for 3 kilo of rice and 2 kilo of fish is less than 400 pesos suppose and joy paid more than 400 pesos and each kilo of rice cost 45 pesos what could it be the greatest amount he will pay for 2 kilos of fish to the nearest pesos

3r+2f < 400

3*45 = 135, so 2f < 265

The total amount andrew paid for 3 kilos of rice and 2 kilos of fish is less than p400. Suppose andrew paid more than p400 and each kilo of rice costs p45. What could be the greatest amount he will pay for 2 kilos of fish to the nearest pesos?

To find the greatest amount Joy can pay for 2 kilos of fish, we need to determine the maximum amount Joy can spend on rice.

Given that Joy paid more than 400 pesos and the total cost of 3 kilos of rice is less than 400 pesos, we can calculate the maximum amount Joy can spend on rice.

Let's assume Joy can spend x pesos on rice.

The cost of 3 kilos of rice is 45 pesos per kilo, so the total cost of rice would be 3 * 45 = 135 pesos.

Since the total cost of rice is less than 400 pesos, we know that x < 135.

To find the maximum amount Joy can pay for 2 kilos of fish, we subtract the maximum amount Joy can spend on rice from the total amount she paid:

400 pesos - x pesos = amount Joy can spend on 2 kilos of fish.

To find the greatest amount to the nearest peso, we need to find the largest possible value for x that satisfies x < 135 and 400 - x > 0.

Since we want to find the maximum possible value for the amount spent on fish, the greatest amount Joy can spend on 2 kilos of fish is when she spends the least amount on rice.

In this case, since the cost of 3 kilos of rice is 135 pesos, Joy can spend the maximum amount on fish:

400 - 135 = 265 pesos.

Therefore, the greatest amount Joy can pay for 2 kilos of fish, to the nearest peso, is 265 pesos.

To find the greatest amount Joy could pay for 2 kilos of fish, we need to determine the maximum amount he can spend given that the total amount for 3 kilos of rice and 2 kilos of fish is less than 400 pesos.

Let's break down the problem step by step:

1. Determine the cost of 3 kilos of rice:
Since each kilo of rice costs 45 pesos, the total cost of 3 kilos of rice would be: 3 kilos * 45 pesos/kilo = 135 pesos.

2. Set up the inequality for the total cost of rice and fish:
Let's assume the cost of 2 kilos of fish is x pesos. According to the problem, the total amount spent on rice and fish should be less than 400 pesos. Therefore, we can write the following inequality:
135 pesos + x pesos < 400 pesos.

3. Solve the inequality for the greatest amount Joy can pay for 2 kilos of fish:
Subtract 135 pesos from both sides of the inequality:
x pesos < 400 pesos - 135 pesos,
x pesos < 265 pesos.

The greatest amount Joy can pay for 2 kilos of fish is 265 pesos, rounded to the nearest peso.