Craig, Daniel and Edward shared an amount of money. Craig took 1/3 of the total amount of money. Daniel had twice as much money as Edward. The boys have $360 altogether. How much money does Edward have?
c = 1/3 * 360 = 120
e + 2e = 360 - 120 = 240
e = 80
Craig took 1/3 : 360 * 1/3 = 120
=> $120
Daniel had twice as much money as
Edward : 2x + x = 360 - 120
3x = 240
x = 80
=> Edward : $80
To solve this problem, we can break it down into smaller steps and use algebra. Let's start by assigning variables to the unknowns:
Let's say the total amount of money shared among the boys is 'x'.
Craig took 1/3 of the total amount, so Craig has (1/3)x.
Daniel had twice as much money as Edward, so let's say Edward has 'y' dollars, then Daniel has 2y dollars.
Now let's form an equation based on the information provided:
(1/3)x + 2y + y = x
Next, simplify the equation:
(1/3)x + 3y = x
Now, let's solve for 'x' in terms of 'y':
(1/3)x = 3y
x = 9y
We also know that the boys have a total of $360, so we can substitute this into the equation:
9y = 360
Next, let's solve for 'y':
y = 360/9
y = 40
Therefore, Edward has $40.