A 30-volt source battery is connected in series with the 6-load resistors namely 1 ohm, 2 ohms, 3 ohms, R ohms, 5 ohms, and 6 ohms respectively. If the total power is 30 watts, find the value of R in resistance and its current drawn as well as the total resistance

(a) provide solution
(b) provide circuit diagram

P = E^2/R = 30^2/(1+2+3+R+5+6) = 30

(1+2+3+R+5+6) = 30
R = 13