An ideal mixing (total volume inlet = total volume outlet) of two incompressible fluids which is
between water and methanol (SG =0.85) is coming from two inlets. At inlet 1, water enter at 9 m/s
and at inlet 2, methanol enters at 7 m/s. The diameter of inlet 1 and 2 is 4 cm and 3 cm. If the
outlet diameter is same as inlet 2, calculate the mixing velocity and density of the mixture at the
outlet.
Inlet 1
R = 2/100
A = pi R^2 = 1.256*10^-3 m^2
Volume/s = 9 m/s * 1.256*10^-3 m^2 = 11.3*10^-3 m^3/s
mass/s = 10^3 kg/m^3 * 11.3*10^-3 m^3/s = 11.3 kg/s
Inlet 2
R =1.5/100
A = pi R^2 = 0.7065*10^-3 m^2
Volume/s = 7 m/s * 0.7065*10^-3 m^2 = 4.95*10^-3 m^3/s
mass/s = 0.85 * 10^3 kg/m^3 * 4.95*10^-3 m^3/s = 4.20 kg/s
I think you can take it from there.