an object of mass 5kg in plane on a plane inclined at an angle of 30 degree to the horizontal. calculate the force on the object perpendicular to the plane when the object is at rest
m g cos 30
To calculate the force perpendicular to the plane when the object is at rest, we need to consider the forces acting on the object.
1. The weight of the object acts vertically downward. It can be calculated as:
Weight = mass * acceleration due to gravity
= 5 kg * 9.8 m/s^2
= 49 N
2. The weight can be resolved into two components: one parallel to the plane and one perpendicular to the plane.
Weight parallel to the plane = Weight * sin(θ)
= 49 N * sin(30°)
= 24.5 N
Weight perpendicular to the plane = Weight * cos(θ)
= 49 N * cos(30°)
= 42.43 N
Since the object is at rest, the force perpendicular to the plane is equal in magnitude but opposite in direction to the weight perpendicular to the plane.
Therefore, the force on the object perpendicular to the plane when it is at rest is 42.43 N, directed upward.