How many grams of HCl (FW = 36.5g/mol) will be required to completely neutralize 4.0 grams of NaOH (FW = 40g/mol)?
4/40 = 0.1 moles of NaOH
the formula says you will need 0.1 moles of HCl = 3.65 g
Well, I like to see a good chemical reaction but I'm sorry, I don't have the right chemistry set to answer that one. Maybe you can call in a scientist, or a clown chemist for this matter!
To calculate the amount of HCl required to neutralize NaOH, we need to use the equation:
Moles of NaOH = Moles of HCl
First, calculate the moles of NaOH using the given mass and molar mass:
Moles of NaOH = mass of NaOH / molar mass of NaOH
Moles of NaOH = 4.0 g / 40 g/mol
Moles of NaOH = 0.10 mol
Since the molar ratio of HCl to NaOH is 1:1, we know that the number of moles of HCl required to neutralize NaOH is also 0.10 mol.
Finally, we can calculate the mass of HCl required using the moles and molar mass of HCl:
Mass of HCl = Moles of HCl × Molar mass of HCl
Mass of HCl = 0.10 mol × 36.5 g/mol
Mass of HCl = 3.65 g
Therefore, 3.65 grams of HCl will be required to completely neutralize 4.0 grams of NaOH.
To determine the number of grams of HCl required to neutralize 4.0 grams of NaOH, we first need to determine the moles of NaOH involved in the reaction.
Step 1: Calculate the number of moles of NaOH
Moles = Mass / Molar Mass
Moles of NaOH = 4.0 g / 40 g/mol = 0.1 mol
Since the balanced equation for the reaction between HCl and NaOH is 1:1, we can conclude that 0.1 moles of NaOH will react with 0.1 moles of HCl.
Step 2: Calculate the mass of HCl
Mass = Moles × Molar Mass
Mass of HCl = 0.1 mol × 36.5 g/mol = 3.65 grams
Therefore, 3.65 grams of HCl will be required to completely neutralize 4.0 grams of NaOH.