Determine the mass of carbon dioxide (in g) produced from the complete combustion of 512.1 g of C8H18 with excess oxygen. Report your answer to the proper number of significant digits without units.
Write this down. It will solve all of them.
Step 1. Write and balance the equation.
2C8H18 + 25O2 ==> 16CO2 + 18H2O
Step 2. Convert what you have (in this case C8H18) into moles.
moles = g/molar mass = 512.1/114.23 = 4.4831
Step 3. Convert moles of what you have (C8H18) into moles of what you want (CO2) by using the coefficients in the balanced equation.
4.4831 mols C8H18 x (16 moles CO2/2 mols C8H18) = 4.4831 x 16/2 = 35.864 moles CO2.
Step 4. Now convert moles to grams.
g CO2 = mols CO2 x molar mass CO2 = ?. Then round the answer to 4 digits.
Post your work if you get stuck. Keep this post handy. It will take care of all of the stoichiometry problems you may have. Use this as a template for other stoichiometry problem.
1578.0
To determine the mass of carbon dioxide produced from the complete combustion of C8H18, we need to understand the balanced equation for the reaction and use the mole ratio to calculate the mass.
The balanced equation for the complete combustion of C8H18 is:
C8H18 + 12.5O2 â 8CO2 + 9H2O
From the balanced equation, we can see that for every 1 mole of C8H18 that reacts, 8 moles of CO2 are produced.
To calculate the moles of C8H18:
Use the molar mass of C8H18 (114.22 g/mol) to convert the given mass of C8H18 (512.1 g) to moles:
Moles of C8H18 = 512.1 g / 114.22 g/mol = 4.484 mol C8H18
Using the mole ratio from the balanced equation, we can determine the moles of CO2 produced:
Moles of CO2 = 4.484 mol C8H18 Ă (8 mol CO2 / 1 mol C8H18) = 35.872 mol CO2
Now, we can use the molar mass of CO2 (44.01 g/mol) to convert the moles of CO2 to grams:
Mass of CO2 = 35.872 mol CO2 Ă 44.01 g/mol = 1581.75 g
Finally, we report the answer to the proper number of significant digits without units:
The mass of carbon dioxide produced from the complete combustion of 512.1 g of C8H18 is 1581.8 g.