Green plants use light from the Sun to drive photosynthesis. Photosynthesis is a chemical reaction in which water H2O and carbon dioxide CO2 chemically react to form the simple sugar glucose C6H12O6 and oxygen gas O2.
What mass of water is consumed by the reaction of 2.34g of carbon dioxide?
Here is a four step procedure that will work stoichiometry problems.
Step 1. Write and balance the equation. I'll do that for you.
6CO2 + 6H2O ==> C6H12O6 + 6O2
Step 2. Convert what you are given in the problem into mols. Moles = grams/molar mass.
Step 3. Using the coefficients in the balanced equation, convert mols of what you have in step 2 into moles of what you want.
Step 4. Convert from step 3 into grams of moles or whatever directed in the problem. If grams then g = mols x molar mass
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To determine the mass of water consumed by the reaction of carbon dioxide, we need to use the balanced chemical equation for photosynthesis, which tells us the stoichiometry of the reaction.
The balanced equation for photosynthesis is:
6CO2 + 6H2O → C6H12O6 + 6O2
From the equation, we can see that for every 6 moles of carbon dioxide (CO2) reacted, 6 moles of water (H2O) are consumed.
To determine the mass of water consumed, we need to convert the mass of carbon dioxide given (2.34g) to moles, and then use the stoichiometry to find the moles of water consumed.
First, we need to find the molar mass of carbon dioxide (CO2):
Carbon (C) has a molar mass of 12.01 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol.
So, the molar mass of CO2 = 12.01 g/mol + 16.00 g/mol + 16.00 g/mol = 44.01 g/mol.
Next, we'll calculate the number of moles of CO2:
Moles = Mass / Molar mass = 2.34 g / 44.01 g/mol = 0.053 moles of CO2.
Using the balanced equation, we can see that for every 6 moles of CO2, 6 moles of H2O are consumed.
So, if 0.053 moles of CO2 react, the number of moles of H2O consumed is also 0.053 moles.
Finally, we need to calculate the mass of water consumed:
Moles = Mass / Molar mass
0.053 moles = Mass / 18.02 g/mol (molar mass of H2O)
Mass = 0.053 moles * 18.02 g/mol = 0.955 g
Therefore, the mass of water consumed by the reaction of 2.34 g of carbon dioxide is 0.955 g.