A bucket filled with water is tied to a piece of string and whirled in a vertical plane.(I)at which position (x or y) will the bucket be heavier and explain.(II) give a reason why the water does not pour out at x.

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Answer for the question

(I) When the bucket is whirled in a vertical plane, the position at which it will be heavier is the bottommost position, represented by the y-axis. This is because at the bottommost position, the gravitational force acting on the bucket and its contents (water) is at its maximum value. The weight of the bucket, combined with the weight of the water inside, creates a downward force due to gravity. Therefore, the bucket will be heavier at the y position.

(II) The reason the water does not pour out at the x position is due to the concept of centripetal force.

Centripetal force is the force that acts towards the center of circular motion, in this case, the string. It is responsible for keeping an object moving in a circular path. When the bucket is whirled in a vertical plane, the centripetal force exerted by the string on the bucket and water acts inward, towards the center of the circular motion.

As long as the speed of rotation is sufficient and the string is securely tied to the bucket, the centripetal force will be strong enough to prevent the water from pouring out. The water is pushed against the bottom of the bucket due to the centripetal force, forming a curved surface. The curved surface, along with the cohesive forces between the water molecules, helps to keep the water inside the bucket and prevent it from spilling out at the x position.

In summary, the combination of centripetal force and cohesive forces within the water enables it to remain inside the bucket and not pour out at the x position.