Question

A stunt person performs a stunt where they run off the top of one building into a window two stories below (7meters down) in an adjacent building that is 6 meters away. How fast does the stunt person have to run horizontally in order to land in the window?

Answer 1

falls 7 meters. How long ?

(1/2) g t^2 = 7 meters
t^2 = 14 / 9.81
t = 1.195 seconds ---- Better be there by then
6 meters = u t
u = 6 meters / 1.195 seconds
= 5.02 meters/second