Use this information: 4 Ag(s)+2 H2S(g) + O2(g) --> 2 Ag2S(s) +2 H2O(l)
What is the mole ratio of H2S(g) to Ag2(s)
A. 2/1
B. 2/2
C. 2/4
D. 4/2
I don't see an Ag2. You must mean Ag2S(s)
Look at the coefficients. So you want (H2S)/(Ag2S). That will be
2H2S
-------- = 2/2 = 1/1
2Ag2S
Technically I was always taught to reduce fractions to their lowest value; therefore I would count 2/2 wrong but that's the only answer that fits. 1/1 is the correct answer.
Oh, chemistry jokes. They never get old. But seriously, let's solve this equation. In the equation, we can see that there are 2 moles of H2S reacting with 2 moles of Ag2S. So, the mole ratio of H2S to Ag2S is 2/2, which is answer choice B. Just remember, when it comes to mole ratios, always keep it in balance!
To determine the mole ratio of H2S(g) to Ag2S(s) in the given reaction:
4 Ag(s) + 2 H2S(g) + O2(g) --> 2 Ag2S(s) + 2 H2O(l)
We need to compare the coefficients of H2S(g) and Ag2S(s).
The coefficient of H2S(g) is 2, and the coefficient of Ag2S(s) is 2.
Therefore, the mole ratio of H2S(g) to Ag2S(s) is 2/2.
So, the correct choice is B. 2/2.
To determine the mole ratio of H2S(g) to Ag2S(s) in the given chemical reaction, we need to examine the balanced equation:
4 Ag(s) + 2 H2S(g) + O2(g) --> 2 Ag2S(s) + 2 H2O(l)
From the equation, we can see that the coefficient of H2S is 2, and the coefficient of Ag2S is also 2. The mole ratio compares the number of moles of different substances in a chemical equation, so the mole ratio of H2S(g) to Ag2S(s) is 2:2.
Simplifying this ratio gives us 1:1. Therefore, the mole ratio of H2S(g) to Ag2S(s) is B. 2/2.