A car is running at a speed of 80m/s. It is then decelerated at the rate of 10m/s2. When will it stop?
(80 m/s) / (10 m/s^2) = ? s
To find out when the car will stop, we can use the following steps:
Step 1: Determine the initial velocity (u) of the car.
Given: Initial velocity (u) = 80 m/s
Step 2: Determine the deceleration (a) of the car.
Given: Deceleration (a) = -10 m/s^2 (negative because it's decelerating)
Step 3: Find the time taken (t) for the car to stop.
We can use the equation of motion: v = u + at, where v is the final velocity.
Since the car stops, the final velocity (v) is 0 m/s.
So, the equation becomes: 0 = 80 + (-10)t
Rearranging the equation: -80 = -10t
Dividing both sides by -10: -80 / -10 = t
t = 8 seconds
Therefore, the car will stop after 8 seconds.
To find out when the car will stop, we need to use the equation of motion relating velocity, acceleration, and time. This equation is given by:
v = u + at
Where:
v = final velocity (which is 0 since the car stops)
u = initial velocity (80 m/s)
a = acceleration (deceleration in this case, -10 m/s^2)
t = time
Rearranging the equation to solve for time:
0 = 80 + (-10)t
Simplifying the equation:
-80 = -10t
Now, divide both sides of the equation by -10:
t = -80 / -10
Therefore, the car will stop in 8 seconds.