Calculate the mass, in grams, of O2 that would be produced following the reaction of 72.36 grams of potassium chlorate (KClO3).
2 KClO3(s) → 2 KCl(s) + 3 O2(g)
how many moles KClO3 in 72.36g?
O2 produced will be 3/2 that many moles.
convert back to grams
2 KClO3(s) → 2 KCl(s) + 3 O2(g)
mols KClO3 = grams/molar mass = 72.36/122.55 = ? Check those numbers.
mols O2 produced = mols KClO3 x (3 mols O2/2 mols KClO3) = ?
Then grams O2 = mols O2 x molar mass O2 = ?
Post your work if you get stuck.
To calculate the mass of O2 produced, we need to use the molar ratio between KClO3 and O2 in the balanced chemical equation.
The molar mass of KClO3 (potassium chlorate) is:
K: 39.10 g/mol
Cl: 35.45 g/mol
O: 16.00 g/mol
Total: 39.10 + 35.45 + (3 * 16.00) = 122.55 g/mol
Now, we can set up the following ratio using the stoichiometry from the balanced equation:
2 moles of KClO3 : 3 moles of O2
To find the number of moles of KClO3, we divide the given mass by the molar mass:
Number of moles of KClO3 = 72.36 g / 122.55 g/mol = 0.59 mol
Since the molar ratio is 2:3, the number of moles of O2 produced can be calculated as:
Number of moles of O2 produced = 0.59 mol * (3 moles O2 / 2 moles KClO3) = 0.89 mol
Finally, we can find the mass of O2 produced using its molar mass:
Mass of O2 produced = 0.89 mol * 32.00 g/mol = 28.48 g
Therefore, the mass of O2 produced following the reaction of 72.36 grams of potassium chlorate is 28.48 grams.
To calculate the mass of oxygen (O2) produced from the reaction of potassium chlorate (KClO3), you need to use stoichiometry.
Stoichiometry is the calculation of reactants and products in chemical reactions based on their balanced equation. In this case, the balanced equation is:
2 KClO3(s) → 2 KCl(s) + 3 O2(g)
From the equation, you can see that for every 2 moles of KClO3, 3 moles of O2 are produced. To calculate the mass of O2, follow these steps:
Step 1: Calculate the number of moles of KClO3.
To do this, divide the given mass of KClO3 by its molar mass. The molar mass of KClO3 can be found by adding up the atomic masses of potassium (K), chlorine (Cl), and three oxygen (O) atoms.
Molar mass of KClO3 = (39.1 g/mol) + (35.5 g/mol) + (16.0 g/mol × 3) = 122.55 g/mol
Number of moles of KClO3 = Mass of KClO3 / Molar mass of KClO3
= 72.36 g / 122.55 g/mol
Step 2: Determine the number of moles of O2 produced using the mole ratio from the balanced equation.
From the equation, you can see that for every 2 moles of KClO3, 3 moles of O2 are produced. So, multiply the number of moles of KClO3 by the mole ratio:
Number of moles of O2 = Number of moles of KClO3 × (3 moles of O2 / 2 moles of KClO3)
Step 3: Calculate the mass of O2 using the number of moles and the molar mass of O2.
The molar mass of O2 can be found by adding up the atomic masses of two oxygen (O) atoms:
Molar mass of O2 = 16.0 g/mol × 2 = 32.0 g/mol
Mass of O2 = Number of moles of O2 × Molar mass of O2
Now, you can substitute the calculated values into the equation to find the mass of O2.