What is the range of this data set?
27, 5, 11, 13, 10, 8, 14, 18, 7
A.(22)
B.(7.5)
C.(11)
D.(16)
Use the list below to find the lower quartile.
27, 5, 11, 13, 10, 8, 14, 18, 7
A.(7)
B.(7.5)
C.(8)
D.(8.5)
Use the list below to find the upper quartile.
27, 5, 11, 13, 10, 8, 14, 18, 7
A.(11)
B.(13)
C.(14)
D.(16)
What is the interquartile range of this data set?
5, 5, 6, 7, 9, 11, 14, 17, 21, 23
A.(7)
B.(9)
C.(11)
D.(13)
What is the interquartile range of this data set?
4, 5, 7, 9, 10, 14, 16, 24
A.(6)
B.(7)
C.(8)
D.(9)
Please help!!
To find the range of a data set, subtract the smallest value from the largest value.
In the given data set: 27, 5, 11, 13, 10, 8, 14, 18, 7
The largest value is 27 and the smallest value is 5.
Range = Largest value - Smallest value
Range = 27 - 5
Range = 22
So the range of this data set is 22. The answer is A.(22).
To find the lower quartile, divide the data set into two halves and find the median of the lower half.
In the given data set: 27, 5, 11, 13, 10, 8, 14, 18, 7
Arranging the data set in ascending order: 5, 7, 8, 10, 11, 13, 14, 18, 27
The lower half of the data set is: 5, 7, 8, 10, 11
The median of the lower half is the value in the middle, which is 8.
So the lower quartile of this data set is 8. The answer is C.(8).
To find the upper quartile, divide the data set into two halves and find the median of the upper half.
In the given data set: 27, 5, 11, 13, 10, 8, 14, 18, 7
Arranging the data set in ascending order: 5, 7, 8, 10, 11, 13, 14, 18, 27
The upper half of the data set is: 13, 14, 18, 27
The median of the upper half is the value in the middle, which is 18.
So the upper quartile of this data set is 18. The answer is C.(14).
To find the interquartile range, subtract the lower quartile from the upper quartile.
The lower quartile is 8 and the upper quartile is 18.
Interquartile range = Upper quartile - Lower quartile
Interquartile range = 18 - 8
Interquartile range = 10
So the interquartile range of this data set is 10. The answer is C.(11).
To find the interquartile range, subtract the lower quartile from the upper quartile.
The lower quartile is 7 and the upper quartile is 16.
Interquartile range = Upper quartile - Lower quartile
Interquartile range = 16 - 7
Interquartile range = 9
So the interquartile range of this data set is 9. The answer is D.(9).
I hope this helps!
To find the range of a data set, you need to subtract the smallest value from the largest value in the set. In this case, the smallest value is 5 and the largest value is 27, so the range is 27 - 5 = 22. Therefore, the answer is (A) 22.
To find the lower quartile, you need to find the median of the lower half of the data set. First, you need to order the data set from least to greatest: 5, 7, 8, 10, 11, 13, 14, 18, 27. In this case, the lower half of the data set is 5, 7, 8, 10. Since the number of values is even, you need to find the median of the two middle values, which are 7 and 8. To find the median of 7 and 8, you add them together and divide by 2: (7 + 8) / 2 = 15 / 2 = 7.5. Therefore, the answer is (B) 7.5.
To find the upper quartile, you follow a similar process but with the upper half of the data set. In this case, the upper half of the ordered data set is 11, 13, 14, 18, 27. Since the number of values is odd, you need to find the median, which is 14. Therefore, the answer is (C) 14.
The interquartile range is the difference between the upper quartile and the lower quartile. In this case, the upper quartile is 14 and the lower quartile is 7.5. Therefore, the interquartile range is 14 - 7.5 = 6.5. However, none of the given options match this result. It seems there might be a mistake with the provided choices.
If you have any further questions or if there's anything else I can help you with, please let me know!
Here are the answers I have so far..
A.(22)
B.(7.5)
D.(16)
C.(11)
D.(9)
I got it all correct, let me know if this helped or not!
no, no help all
Just giving answers to tests is cheating and morally wrong.