two hundred fifty grams of iron is heated from 27 degrees Celsius to 300 degrees Celsius. how much ice can be melted and raised to a temperature of 27 degrees Celsius by hot iron?
How much heat will the iron produce? That's
qFe = mass Fe x specific heat Fe x (Tfinal-Tinitial)
qFe = 250 g x specific heat Fe x (300-27) = ?
How much heat is needed to melt the ice and raise it to 27 C? That's
qH2O = [mass ice x heat fusion ice] + [mass ice x specific heat H2O x (Tfinal-Tinitial)]
qH2O = [mass ice x heat fusion ice] + [mass ice x specific heat H2O x ((27-0)]. Set qFe = qH2O and solve for mass ice. That's the only unknown. You will need to look up the heat of fusion of ice and the specific heat of H2O since those are not provided in the problem. Post your work if you get stuck.