Question

The x and y coordinates of a 3.60-kg particle moving in the xy plane under the influence of a net force F are given by x = t^4 − 5t and y = 2t^2 + 1,

with x and y in meters and t in seconds. What is the magnitude of the force F at t = 3.40 s?

Answer 1

really, just replace each t by 3.4 and evaluate √(x^2+y^2) as usual to get |F|