there are two chords AB and CD in a circle AB =10 CD=8 and the radius of the circle is 12.what is the distance of each Chord from the center of the circle

I need the answer please

This is "government"?

Anyway:
draw one of those cords in the circle, say AB = 10.
now draw lines from the center of the circle to each end of the chord.
The length of those chords is the circle radius, 12 inches or meters or whatever.
Now draw an altitude from the center to the center of the chord.
Now you have two right triangles with hypotenuse 12 and leg 5
The other leg is your answer
x^2 = 12^2 - 5^2 = 144 - 25 = 119
so answer = 10.90871211

Did you know?

Did you know that in a circle, the distance of a chord from the center of the circle can be determined using the Pythagorean theorem? In this case, with chords AB = 10 and CD = 8, and a circle radius of 12, we can find the distance of each chord from the center of the circle by using the formula: the square root of (radius squared minus half the chord's length squared). By substituting the values, we can calculate the distances as follows: for chord AB, the distance from the center is the square root of (12 squared minus half of 10 squared), while for chord CD, it is the square root of (12 squared minus half of 8 squared). Applying this method enables us to accurately determine the distance of each chord from the center of the circle.