What is your displacement when you travel north 100m, 60 degrees East of North then 60 m, 30 degrees West of north
i forgot, it needs graph thankyou
no graphs here.
But get out your graph paper and draw the vectors.
Your second vector needs a length.
To find the displacement in this situation, we need to break down the movements into their components.
First, let's consider the movement north for 100 meters. Since there is no east or west component, the northward movement contributes 100 meters in the y-direction.
Next, we need to break down the movement of 60 degrees east of north. This movement has both north and east components. To find these components, we need to use trigonometry. The north component can be found using sin(60°) = North component / 60 m. Solving for the north component: North component = 60 m * sin(60°) = 60 m * 0.866 = 51.96 m (approximately 52 meters). Similarly, the east component can be found using cos(60°) = East component / 60 m. Solving for the east component: East component = 60 m * cos(60°) = 60 m * 0.5 = 30 m.
Lastly, let's break down the movement of 60 degrees west of north. This movement also has north and west components. Using similar trigonometric calculations, we find that the north component is 60 m * sin(60°) = 52 m (approximately) and the west component is 60 m * cos(60°) = 30 m.
Now, the displacement is a vector sum of the individual displacements. To find the total north component, we add the north components calculated earlier: 100 m + 52 m + 52 m = 204 m. Similarly, the east component is calculated by adding the east component of movement 2 and subtracting the west component of movement 3: 30 m - 30 m = 0 m.
Therefore, the displacement is 204 m to the north with no eastward displacement.