find 2 consecutive odd integers such that he sum of the smaller and 3 times the larger is 330
x + 3(x+2) = 330
Sure! Let's solve this math problem with a touch of humor.
Let's call the smaller odd integer x, and the larger one x + 2 because consecutive odd integers have a difference of 2. Now, according to the problem, the sum of the smaller integer (x) and 3 times the larger integer (3(x+2)) is equal to 330. Let's set up the equation:
x + 3(x + 2) = 330
Expanding the equation, we get:
x + 3x + 6 = 330
Combining like terms:
4x + 6 = 330
To isolate x, we subtract 6 from both sides:
4x = 324
Finally, we divide both sides by 4:
x = 81
So, the smaller odd integer is 81. And as we know, consecutive odd integers have a difference of 2, so the larger integer is:
81 + 2 = 83
Therefore, the two consecutive odd integers that satisfy the given conditions are 81 and 83. Voila!
Let's assume that the smaller odd integer is x.
The next odd integer would then be x + 2, since consecutive odd integers are separated by 2.
According to the problem, the sum of the smaller integer (x) and 3 times the larger integer (3(x + 2)) is equal to 330.
To write this as an equation:
x + 3(x + 2) = 330
Now, let's solve this equation step-by-step:
First, distribute the 3 to both terms in the parentheses:
x + 3x + 6 = 330
Next, combine like terms:
4x + 6 = 330
Now, subtract 6 from both sides of the equation:
4x = 330 - 6
4x = 324
Next, divide both sides of the equation by 4:
4x/4 = 324/4
x = 81
So, the smaller odd integer is 81.
To find the next odd integer, add 2 to 81:
81 + 2 = 83
Therefore, the two consecutive odd integers that satisfy the given condition are 81 and 83.
To find two consecutive odd integers, let's assume the first odd integer as 'x' and the next odd integer as 'x+2'.
According to the problem, the sum of the smaller integer and 3 times the larger integer is 330. So, the equation can be written as:
x + 3(x+2) = 330
Now, let's solve the equation:
x + 3x + 6 = 330
Combining like terms:
4x + 6 = 330
Subtracting 6 from both sides of the equation:
4x = 324
Dividing both sides by 4:
x = 81
Therefore, the first odd integer is 81.
To find the next odd integer, we add 2 to the first odd integer:
81 + 2 = 83
So, the two consecutive odd integers are 81 and 83.