Find the weight of the same object on earth where the gravitational attraction has been reduced to 1/10 of the. Earths pull.
So it will be 1/10 as much.
To find the weight of an object on Earth when the gravitational attraction is reduced to 1/10 of Earth's pull, we need to apply the principles of gravity and Newton's second law of motion.
First, let's establish some information:
- The weight of an object is the force with which it is attracted towards the center of the Earth due to gravity.
- On Earth, the acceleration due to gravity is approximately 9.8 m/s².
Now, let's calculate the weight of the object on Earth when the gravitational attraction is reduced to 1/10 of Earth's pull.
Step 1: Determine the original weight on Earth
The weight (W) of an object is given by the formula:
W = m × g
where m is the mass of the object and g is the acceleration due to gravity.
Step 2: Calculate the reduced gravity
If the gravitational attraction is reduced to 1/10 of Earth's pull, then the new acceleration due to gravity (g') will be:
g' = 1/10 × g
Step 3: Calculate the weight with reduced gravity
Using the new acceleration due to gravity, the weight of the object with reduced gravity is:
W' = m × g'
Now, let's assume the mass of the object is 1 kilogram (kg) for simplicity.
Step 4: Calculate the weight of the object on Earth with reduced gravity
We will substitute the values into the formulas:
W = m × g
W' = m × g'
W = 1 kg × 9.8 m/s²
W' = 1 kg × (1/10 × 9.8 m/s²)
W ≈ 9.8 kg·m/s² (approximately)
W' ≈ 0.98 kg·m/s² (approximately)
Therefore, the weight of the object on Earth is approximately 9.8 kg·m/s², while the weight of the same object when the gravitational attraction is reduced to 1/10 of Earth's pull is approximately 0.98 kg·m/s².